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Question Number 81879 by zainal tanjung last updated on 16/Feb/20
The value of determinant determinant (((−1),(    1),(    1)),((    1),(−1),(    1)),((    1),(     1),(−1)))  is equal to
Thevalueofdeterminant|111111111|isequalto
Commented by john santu last updated on 16/Feb/20
−1(0)−1(−2)+1(2) = 4
1(0)1(2)+1(2)=4
Commented by mathmax by abdo last updated on 16/Feb/20
=−1× determinant (((−1        1)),((1            −1)))−1× determinant (((1         1)),((1         −1)))+1× determinant (((1       1)),((−1   1)))  =−(0)−(−2)+(2)  =4
=1×|1111|1×|1111|+1×|1111|=(0)(2)+(2)=4

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