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27t73-11-and-R-0-then-t-how-is-explontry-solution-




Question Number 193525 by mustafazaheen last updated on 16/Jun/23
     ((27t73)/(11))       and R=0   then t=?        how is explontry solution
$$\:\:\:\:\:\frac{\mathrm{27t73}}{\mathrm{11}} \\ $$$$\:\:\:\:\:\mathrm{and}\:\mathrm{R}=\mathrm{0}\:\:\:\mathrm{then}\:\mathrm{t}=? \\ $$$$\:\:\:\:\:\:\mathrm{how}\:\mathrm{is}\:\mathrm{explontry}\:\mathrm{solution} \\ $$
Answered by MM42 last updated on 16/Jun/23
3−7+t−7+2=11k⇒−9+t=11k⇒t=9
$$\mathrm{3}−\mathrm{7}+{t}−\mathrm{7}+\mathrm{2}=\mathrm{11}{k}\Rightarrow−\mathrm{9}+{t}=\mathrm{11}{k}\Rightarrow{t}=\mathrm{9} \\ $$
Answered by BaliramKumar last updated on 16/Jun/23
(3−7)+(t−7)+(2−0) = 11k  −4+t−7+2 = 11k  t−9 = 11k  t = 11k+9  k = 0  t=9
$$\left(\mathrm{3}−\mathrm{7}\right)+\left(\mathrm{t}−\mathrm{7}\right)+\left(\mathrm{2}−\mathrm{0}\right)\:=\:\mathrm{11k} \\ $$$$−\mathrm{4}+\mathrm{t}−\mathrm{7}+\mathrm{2}\:=\:\mathrm{11k} \\ $$$$\mathrm{t}−\mathrm{9}\:=\:\mathrm{11k} \\ $$$$\mathrm{t}\:=\:\mathrm{11k}+\mathrm{9} \\ $$$$\mathrm{k}\:=\:\mathrm{0} \\ $$$$\mathrm{t}=\mathrm{9} \\ $$

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