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lim-x-1-2arctan-2-x-pi-8-x-2-1-




Question Number 193677 by lapache last updated on 18/Jun/23
lim_(x→1)  ((2arctan^2 x−(π/8))/(x^2 −1))=...
$${li}\underset{{x}\rightarrow\mathrm{1}} {{m}}\:\frac{\mathrm{2}{arctan}^{\mathrm{2}} {x}−\frac{\pi}{\mathrm{8}}}{{x}^{\mathrm{2}} −\mathrm{1}}=… \\ $$
Answered by cortano12 last updated on 18/Jun/23
$$\:\:\underline{\underbrace{\:}} \cancel{\:} \\ $$$$ \\ $$

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