Menu Close

Question-193714




Question Number 193714 by Rupesh123 last updated on 18/Jun/23
Commented by Frix last updated on 18/Jun/23
(√(17±(√(288))))=(√(17±12(√2)))=3±2(√2)  (√(7±(√(48))))=(√(7±4(√3)))=2±(√3)  ⇒  Answer is 2
$$\sqrt{\mathrm{17}\pm\sqrt{\mathrm{288}}}=\sqrt{\mathrm{17}\pm\mathrm{12}\sqrt{\mathrm{2}}}=\mathrm{3}\pm\mathrm{2}\sqrt{\mathrm{2}} \\ $$$$\sqrt{\mathrm{7}\pm\sqrt{\mathrm{48}}}=\sqrt{\mathrm{7}\pm\mathrm{4}\sqrt{\mathrm{3}}}=\mathrm{2}\pm\sqrt{\mathrm{3}} \\ $$$$\Rightarrow \\ $$$$\mathrm{Answer}\:\mathrm{is}\:\mathrm{2} \\ $$
Commented by Mingma last updated on 18/Jun/23
Perfect ��
Commented by Rupesh123 last updated on 18/Jun/23
Perfect ��
Answered by AST last updated on 18/Jun/23
a^2 +c^2 =34,ac=1⇒(a+c)^2 −2ac=34⇒a+c=6  b^2 +d^2 =14,bd=1⇒(b+d)^2 −2bd=14⇒b+d=4  ⇒a−b+c−d=2
$${a}^{\mathrm{2}} +{c}^{\mathrm{2}} =\mathrm{34},{ac}=\mathrm{1}\Rightarrow\left({a}+{c}\right)^{\mathrm{2}} −\mathrm{2}{ac}=\mathrm{34}\Rightarrow{a}+{c}=\mathrm{6} \\ $$$${b}^{\mathrm{2}} +{d}^{\mathrm{2}} =\mathrm{14},{bd}=\mathrm{1}\Rightarrow\left({b}+{d}\right)^{\mathrm{2}} −\mathrm{2}{bd}=\mathrm{14}\Rightarrow{b}+{d}=\mathrm{4} \\ $$$$\Rightarrow{a}−{b}+{c}−{d}=\mathrm{2} \\ $$
Commented by Mingma last updated on 18/Jun/23
Perfect ��
Commented by Rupesh123 last updated on 18/Jun/23
Perfect ��

Leave a Reply

Your email address will not be published. Required fields are marked *