lim-n-1-1-2-1-2-2-1-3-2-1-n-2-

Question Number 194147 by DAVONG last updated on 28/Jun/23

\lim_{n \to + \infty} (\frac{1}{1^{2}} + \frac{1}{2^{2}} + \frac{1}{3^{2}} + \dots + \frac{1}{n^{2}}) = ?

Answered by Frix last updated on 28/Jun/23

\frac{π^{2}}{6}

Answered by 123564 last updated on 03/Jul/23

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