Question-194139

Question Number 194139 by cortano12 last updated on 28/Jun/23

Commented by MM42 last updated on 28/Jun/23

f o r

{l i m}_{x \to 0} \frac{x^{2} + 2 c o s x - 2}{x^{4}} \to h o p

{l i m}_{x \to 0} \frac{2 (x - s i n x)}{4 x^{3}} = \frac{1}{2} \times \frac{1}{6} = \frac{1}{12}

\Rightarrow

Answered by MM42 last updated on 28/Jun/23

h o p \to {l i m}_{x \to 0} \frac{2 x + 2 s i n x}{4 x^{3}} = + \infty

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