Menu Close

Question-194304




Question Number 194304 by 281981 last updated on 02/Jul/23
Answered by cortano12 last updated on 03/Jul/23
    sin (A+B) cos (A+B) sin (A−B) cos (A−B)=(1/2)     sin (2A+2B) sin (2A−2B)= 2     A
$$\:\:\:\:\mathrm{sin}\:\left(\mathrm{A}+\mathrm{B}\right)\:\mathrm{cos}\:\left(\mathrm{A}+\mathrm{B}\right)\:\mathrm{sin}\:\left(\mathrm{A}−\mathrm{B}\right)\:\mathrm{cos}\:\left(\mathrm{A}−\mathrm{B}\right)=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\:\:\:\mathrm{sin}\:\left(\mathrm{2A}+\mathrm{2B}\right)\:\mathrm{sin}\:\left(\mathrm{2A}−\mathrm{2B}\right)=\:\mathrm{2} \\ $$$$\:\:\:\underbrace{\boldsymbol{{A}}} \\ $$
Commented by 281981 last updated on 03/Jul/23
ok sir.tnq
$${ok}\:{sir}.{tnq} \\ $$

Leave a Reply

Your email address will not be published. Required fields are marked *