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Question-194304

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Question Number 194304 by 281981 last updated on 02/Jul/23
Answered by cortano12 last updated on 03/Jul/23
sin (A+B) cos (A+B) sin (A−B) cos (A−B)=(1/2) sin (2A+2B) sin (2A−2B)= 2 A
sin(A+B)cos(A+B)sin(A−B)cos(A−B)=12sin(2A+2B)sin(2A−2B)=2A⏟
Commented by 281981 last updated on 03/Jul/23
ok sir.tnq
oksir.tnq

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