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Question-194518




Question Number 194518 by otchereabdullai@gmail.com last updated on 09/Jul/23
Commented by otchereabdullai@gmail.com last updated on 09/Jul/23
please help me with the b part
$${please}\:{help}\:{me}\:{with}\:{the}\:{b}\:{part} \\ $$
Answered by mr W last updated on 14/Jul/23
Commented by mr W last updated on 14/Jul/23
x=k=150
$${x}={k}=\mathrm{150} \\ $$
Commented by mr W last updated on 14/Jul/23
R=150 N  f_R =0.1×100=10 N  (i): R−f_R =150−10=140 N  (ii): a=((R−f_R )/m)=((140)/(100))=1.4 m/s^2
$${R}=\mathrm{150}\:{N} \\ $$$${f}_{{R}} =\mathrm{0}.\mathrm{1}×\mathrm{100}=\mathrm{10}\:{N} \\ $$$$\left({i}\right):\:{R}−{f}_{{R}} =\mathrm{150}−\mathrm{10}=\mathrm{140}\:{N} \\ $$$$\left({ii}\right):\:{a}=\frac{{R}−{f}_{{R}} }{{m}}=\frac{\mathrm{140}}{\mathrm{100}}=\mathrm{1}.\mathrm{4}\:{m}/{s}^{\mathrm{2}} \\ $$
Commented by otchereabdullai@gmail.com last updated on 16/Jul/23
God bless you prof W
$${God}\:{bless}\:{you}\:{prof}\:{W} \\ $$

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