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If-a-divided-by-b-gives-q-remaining-r-Then-a-b-q-rrr-in-base-b-1-




Question Number 194779 by sniper237 last updated on 15/Jul/23
If  a  divided by b gives q  remaining r  Then  (a/b) = q,rrr...  in base b+1
$${If}\:\:{a}\:\:{divided}\:{by}\:{b}\:{gives}\:{q}\:\:{remaining}\:{r} \\ $$$${Then}\:\:\frac{{a}}{{b}}\:=\:{q},{rrr}…\:\:{in}\:{base}\:{b}+\mathrm{1} \\ $$
Commented by Frix last updated on 15/Jul/23
No problem ��
Commented by Frix last updated on 15/Jul/23
Example?  ((10)/7)=1 remaining 3 but (3/7) in base 7 is .3
$$\mathrm{Example}? \\ $$$$\frac{\mathrm{10}}{\mathrm{7}}=\mathrm{1}\:\mathrm{remaining}\:\mathrm{3}\:\mathrm{but}\:\frac{\mathrm{3}}{\mathrm{7}}\:\mathrm{in}\:\mathrm{base}\:\mathrm{7}\:\mathrm{is}\:.\mathrm{3} \\ $$
Commented by Frix last updated on 15/Jul/23
...on the other hand  2.11111... in base 7 is ((13)/6) in base 10  I don′t get it?!
$$…\mathrm{on}\:\mathrm{the}\:\mathrm{other}\:\mathrm{hand} \\ $$$$\mathrm{2}.\mathrm{11111}…\:\mathrm{in}\:\mathrm{base}\:\mathrm{7}\:\mathrm{is}\:\frac{\mathrm{13}}{\mathrm{6}}\:\mathrm{in}\:\mathrm{base}\:\mathrm{10} \\ $$$$\mathrm{I}\:\mathrm{don}'\mathrm{t}\:\mathrm{get}\:\mathrm{it}?! \\ $$
Commented by sniper237 last updated on 15/Jul/23
Sorry for all
$${Sorry}\:{for}\:{all} \\ $$
Answered by AST last updated on 15/Jul/23
(a/b)=q+(r/b)=q.r(base b) for q<b(Otherwise,express  q in its simplest form in base b)
$$\frac{{a}}{{b}}={q}+\frac{{r}}{{b}}={q}.{r}\left({base}\:{b}\right)\:{for}\:{q}<{b}\left({Otherwise},{express}\right. \\ $$$$\left.{q}\:{in}\:{its}\:{simplest}\:{form}\:{in}\:{base}\:{b}\right) \\ $$

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