Question Number 194831 by necx122 last updated on 16/Jul/23
Commented by necx122 last updated on 16/Jul/23
$${I}'{ve}\:{tried}\:{attempting}\:{this}\:{question}\:{but} \\ $$$${got}\:{stuck}.{Please},\:{I}\:{need}\:{assistance}. \\ $$
Answered by dimentri last updated on 16/Jul/23
![V=π∫_0 ^π sin^2 x dx V=π [ (1/2)x−(1/4)sin 2x ]_0 ^π V= (1/2)π^2](https://www.tinkutara.com/question/Q194832.png)
$$\:\:{V}=\pi\underset{\mathrm{0}} {\overset{\pi} {\int}}\mathrm{sin}\:^{\mathrm{2}} {x}\:{dx}\: \\ $$$$\:\:{V}=\pi\:\left[\:\frac{\mathrm{1}}{\mathrm{2}}{x}−\frac{\mathrm{1}}{\mathrm{4}}\mathrm{sin}\:\mathrm{2}{x}\:\right]_{\mathrm{0}} ^{\pi} \\ $$$$\:\:{V}=\:\frac{\mathrm{1}}{\mathrm{2}}\pi^{\mathrm{2}} \\ $$
Commented by necx122 last updated on 16/Jul/23
$${Thank}\:{you}\:{sir}. \\ $$