Question Number 194844 by sniper237 last updated on 16/Jul/23
$$\left({x}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{2}} +\left({x}+\mathrm{3}\right)^{\mathrm{2}} =\left({x}^{\mathrm{2}} +{ax}+{b}\right)\left({x}^{\mathrm{2}} +{cx}+{d}\right) \\ $$$${Find}\:{a},{b},{c},{d}. \\ $$
Answered by Frix last updated on 17/Jul/23
$$\left({x}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{2}} +\left({x}+\mathrm{3}\right)^{\mathrm{2}} =\left({x}^{\mathrm{2}} −\mathrm{2}{x}+\mathrm{5}\right)\left({x}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{2}\right) \\ $$