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Question-194961




Question Number 194961 by SirMUTUKU last updated on 20/Jul/23
Answered by mahdipoor last updated on 20/Jul/23
log225=log(25×9)=log((100)/4)+log9=  log100−log4+2log3=2−.6021+2×.4771=  2.3521
$${log}\mathrm{225}={log}\left(\mathrm{25}×\mathrm{9}\right)={log}\frac{\mathrm{100}}{\mathrm{4}}+{log}\mathrm{9}= \\ $$$${log}\mathrm{100}−{log}\mathrm{4}+\mathrm{2}{log}\mathrm{3}=\mathrm{2}−.\mathrm{6021}+\mathrm{2}×.\mathrm{4771}= \\ $$$$\mathrm{2}.\mathrm{3521} \\ $$

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