Question Number 194961 by SirMUTUKU last updated on 20/Jul/23
Answered by mahdipoor last updated on 20/Jul/23
$${log}\mathrm{225}={log}\left(\mathrm{25}×\mathrm{9}\right)={log}\frac{\mathrm{100}}{\mathrm{4}}+{log}\mathrm{9}= \\ $$$${log}\mathrm{100}−{log}\mathrm{4}+\mathrm{2}{log}\mathrm{3}=\mathrm{2}−.\mathrm{6021}+\mathrm{2}×.\mathrm{4771}= \\ $$$$\mathrm{2}.\mathrm{3521} \\ $$