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x-17-x-2-x-17-x-2-9-find-the-possible-value-of-X-




Question Number 194952 by pascal889 last updated on 20/Jul/23
x + (√(17−x^2 ))  + x(√(17−x^2  )) =9  find the possible value of  X
$$\boldsymbol{\mathrm{x}}\:+\:\sqrt{\mathrm{17}−\boldsymbol{\mathrm{x}}^{\mathrm{2}} }\:\:+\:\boldsymbol{\mathrm{x}}\sqrt{\mathrm{17}−\boldsymbol{\mathrm{x}}^{\mathrm{2}} \:}\:=\mathrm{9} \\ $$$$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{possible}}\:\boldsymbol{\mathrm{value}}\:\boldsymbol{\mathrm{of}}\:\:\boldsymbol{\mathrm{X}} \\ $$
Answered by Frix last updated on 20/Jul/23
Obviously x=1∨x=4  1+4+1×4=9  4+1+4×1=9
$$\mathrm{Obviously}\:{x}=\mathrm{1}\vee{x}=\mathrm{4} \\ $$$$\mathrm{1}+\mathrm{4}+\mathrm{1}×\mathrm{4}=\mathrm{9} \\ $$$$\mathrm{4}+\mathrm{1}+\mathrm{4}×\mathrm{1}=\mathrm{9} \\ $$

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