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Question Number 195033 by mathlove last updated on 22/Jul/23
any point is the function is  not continous  f(x)=(4x+8)^((ln45)/8)   a) −8                         b) −2  c) no one                  d) 5
$${any}\:{point}\:{is}\:{the}\:{function}\:{is} \\ $$$${not}\:{continous} \\ $$$${f}\left({x}\right)=\left(\mathrm{4}{x}+\mathrm{8}\right)^{\frac{{ln}\mathrm{45}}{\mathrm{8}}} \\ $$$$\left.{a}\left.\right)\:−\mathrm{8}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{b}\right)\:−\mathrm{2} \\ $$$$\left.{c}\left.\right)\:{no}\:{one}\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{d}\right)\:\mathrm{5} \\ $$
Answered by alephzero last updated on 22/Jul/23
not continous ⇒ 4x−8 < 0  ⇒ a) −8
$${not}\:{continous}\:\Rightarrow\:\mathrm{4}{x}−\mathrm{8}\:<\:\mathrm{0} \\ $$$$\left.\Rightarrow\:{a}\right)\:−\mathrm{8} \\ $$
Commented by mathlove last updated on 22/Jul/23
whats domain f(x)?  some solution
$${whats}\:{domain}\:{f}\left({x}\right)? \\ $$$${some}\:{solution} \\ $$
Commented by alephzero last updated on 22/Jul/23
f(x) = (4x+8)^((ln 45)/8)   D = [−2; +∞)
$${f}\left({x}\right)\:=\:\left(\mathrm{4}{x}+\mathrm{8}\right)^{\frac{\mathrm{ln}\:\mathrm{45}}{\mathrm{8}}} \\ $$$${D}\:=\:\left[−\mathrm{2};\:+\infty\right) \\ $$

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