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f-x-arctan-sinx-and-cosa-2-3-faind-f-a-




Question Number 195136 by mathlove last updated on 25/Jul/23
f(x)=arctan(sinx)  and  cosa=(2/3)        faind   f^′ (a)=?
f(x)=arctan(sinx)andcosa=23faindf(a)=?
Answered by som(math1967) last updated on 25/Jul/23
 f ′(x)=(1/(1+sin^2 x))×cosx  f ′(𝛂)=(1/(1+sin^2 𝛂))×cos𝛂   =(1/(1+(5/9)))×(2/3)  =(9/(14))×(2/3)=(3/7)
f(x)=11+sin2x×cosxf(α)=11+sin2α×cosα=11+59×23=914×23=37

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