Question Number 195192 by mustafazaheen last updated on 26/Jul/23
$$ \\ $$$$\underset{{x}\rightarrow\infty} {\mathrm{lim}}\left(\mathrm{sinx}+\frac{\pi}{\mathrm{2}}\right)^{\mathrm{x}} =? \\ $$
Answered by MM42 last updated on 26/Jul/23
$${sinx}+\frac{\pi}{\mathrm{2}}>\mathrm{1} \\ $$$$\Rightarrow{lim}_{{x}\rightarrow+\infty} \:=+\infty\:\:\&\:\:\:{lim}_{{x}\rightarrow−\infty} =\mathrm{0} \\ $$