Question-195208

Question Number 195208 by Mastermind last updated on 27/Jul/23

Answered by BaliramKumar last updated on 27/Jul/23

$$\mathrm{3}\left[\frac{\mathrm{3}\left(\mathrm{3}+\mathrm{1}\right)}{\mathrm{2}}\right]\:=\:\mathrm{18} \\ $$

Commented by BaliramKumar last updated on 27/Jul/23

Answered by mr W last updated on 27/Jul/23

$$\mathrm{3}×{C}_{\mathrm{2}} ^{\mathrm{4}} =\mathrm{3}×\mathrm{6}=\mathrm{18} \\ $$

Commented by mr W last updated on 27/Jul/23

Commented by mr W last updated on 27/Jul/23

$${generally}: \\ $$$${number}\:{of}\:{triangles}\:={m}×{C}_{\mathrm{2}} ^{{n}} =\frac{{mn}\left({n}−\mathrm{1}\right)}{\mathrm{2}} \\ $$

Answered by York12 last updated on 27/Jul/23

$$\left(\mathrm{1}+\mathrm{2}+\mathrm{3}\right)×\mathrm{3}=\mathrm{18} \\ $$

Answered by jaoa_ao1 last updated on 27/Jul/23

$$\mathrm{zjzjmsms} \\ $$

Commented by York12 last updated on 27/Jul/23

$$¿¿ \\ $$