1-3-i-2-n-x-i-i-2-n-1-i-j-2-n-j-3-i-1-j-1-x-i-i-j-1-n-x-j-i-1-j-1-j-i-i-j-1-n-j-i-n-3-i-1-

Question Number 195227 by York12 last updated on 28/Jul/23

α_{1}^{3} [\frac{\underset{i = 2}{\prod^{n}} (x - α_{i})}{\underset{i = 2}{\prod^{n}} (α_{1} - α_{i})}] + \underset{j = 2}{\sum^{n}} (α_{j}^{3} [\frac{\underset{i = 1}{\prod^{j - 1}} (x - α_{i}) \underset{i = j + 1}{\prod^{n}} (x - α_{j})}{\underset{i = 1}{\prod^{j - 1}} (α_{j} - α_{i}) \underset{i = j + 1}{\prod^{n}} (α_{j} - α_{i})}] + α_{n}^{3} [\frac{\underset{i = 1}{\prod^{n - 1}} (x - α_{i})}{\underset{i = 1}{\prod^{n - 1}} (α_{n} - α_{i})}] - x^{3} = 0

s o l v e f o r x . [w h e r e n ⩾ 5]