determinant-

Question Number 195231 by cortano12 last updated on 28/Jul/23

\begin{matrix} \underset{―}{\underset{⏟}{}} \end{matrix}

Answered by MM42 last updated on 28/Jul/23

{l i m}_{x \to 0} \sqrt{\frac{1 - c o s \sqrt{π x}}{x (1 + \sqrt{c o s \sqrt{π x}})}}

= {l i m}_{x \to 0} \sqrt{\frac{\frac{1}{2} π x}{x (1 + \sqrt{c o s \sqrt{π x})}}}

= \sqrt{\frac{π}{4}} = \frac{\sqrt{π}}{2} ✓

Commented by cortano12 last updated on 28/Jul/23

w r o n g

Commented by Frix last updated on 28/Jul/23

I also get \frac{\sqrt{π}}{2}

Commented by mokys last updated on 29/Jul/23

\frac{π}{2}

Facebook Tweet Pin