spillover-sin-2-xcos-2-x-sin-5-x-cos-3-xsin-2-x-sin-3-xcos-2-x-cos-5-x-2-dx- Tinku Tara July 28, 2023 Algebra 0 Comments FacebookTweetPin Question Number 195254 by Spillover last updated on 02/Aug/23 ∫spilloversin2xcos2x(sin5x+cos3xsin2x+sin3xcos2x+cos5x)2dx Answered by Spillover last updated on 02/Aug/23 leta=sinxb=cosxspilloverleta=sinxb=cosxspillovera2=sin2xb2=cos2xa2+b2=sin2x+cos2x=1spilloversin5x+cos3xsin2x+sin3xcos2x+cos5x)2a5+b3a2+a3b2+b5spillover=a2(a3+b3)+b2(a3+b3)=(a2+b2)(a3+b3)a5+b3a2+a3b2+b5=(a2+b2)(a3+b3)buta2+b2=sin2x+cos2x=1a5+b3a2+a3b2+b5=(a3+b3)(a3+b3)=sin3x+cos3xspillover∫sin2xcos2x(sin3x+cos3x)2dx⇒∫tan2xsec2x(1+tan3x)2dxletu=1+tan3xdu=3sec2xtan2xdxspillover∫tan2xsec2xu2.du3sec2xtan2x=∫13duu2=−13u+c∫13duu2=−13u+D=−13(1+tan3x)+D Terms of Service Privacy Policy Contact: info@tinkutara.com FacebookTweetPin Post navigation Previous Previous post: Question-195281Next Next post: dx-cos-3-x-4sin-xcos-x- Leave a Reply Cancel replyYour email address will not be published. Required fields are marked *Comment * Name * Save my name, email, and website in this browser for the next time I comment.