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Question-195411




Question Number 195411 by sonukgindia last updated on 02/Aug/23
Answered by MM42 last updated on 02/Aug/23
lim_(x→∞)  ((2×2^x −(1/3)×9^x +4^x )/(8×4^x +3^x −(1/4)×4^x ))  =lim_(x→∞)  ((−(1/3)9^x )/(((31)/4)×4^x ))=−∞
$${lim}_{{x}\rightarrow\infty} \:\frac{\mathrm{2}×\mathrm{2}^{{x}} −\frac{\mathrm{1}}{\mathrm{3}}×\mathrm{9}^{{x}} +\mathrm{4}^{{x}} }{\mathrm{8}×\mathrm{4}^{{x}} +\mathrm{3}^{{x}} −\frac{\mathrm{1}}{\mathrm{4}}×\mathrm{4}^{{x}} } \\ $$$$={lim}_{{x}\rightarrow\infty} \:\frac{−\frac{\mathrm{1}}{\mathrm{3}}\mathrm{9}^{{x}} }{\frac{\mathrm{31}}{\mathrm{4}}×\mathrm{4}^{{x}} }=−\infty \\ $$

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