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Given-ABC-where-BC-a-AC-b-and-AB-c-If-A-60-Find-the-value-of-1-b-c-a-c-1-c-b-a-b-




Question Number 195517 by cortano12 last updated on 04/Aug/23
   Given ΔABC where BC= a,      AC = b and AB = c . If ∠ A= 60°     Find the value of     (1+(b/c)+(a/c))(1+(c/b)+(a/b)).
GivenΔABCwhereBC=a,AC=bandAB=c.IfA=60°Findthevalueof(1+bc+ac)(1+cb+ab).
Answered by horsebrand11 last updated on 05/Aug/23
 ((b+a)/c) = ((cos (((A−B)/2)))/(sin ((C/2))))   ((a+c)/b)= ((cos (((C−A)/2)))/(sin ((B/2))))
b+ac=cos(AB2)sin(C2)a+cb=cos(CA2)sin(B2)

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