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f-x-1276-x-1-ln-2-4589-domain-f-x-




Question Number 195647 by mathlove last updated on 06/Aug/23
f(x)=((1276)/((x−1)^(ln(2/(4589))) ))  domain f(x)=?
f(x)=1276(x1)ln24589domainf(x)=?
Answered by Tokugami last updated on 17/Sep/23
((1276)/((x−1)^(ln(2)−ln(4589)) ))=1276(x−1)^(ln(4589)−ln(2))   ln(((4589)/2))∉Z→ x−1≥0  x≥1
1276(x1)ln(2)ln(4589)=1276(x1)ln(4589)ln(2)ln(45892)Zx10x1

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