1-0-pi-2-x-2-sin-2-x-dx-1-2-2-0-pi-2-x-tan-x-

Question Number 195846 by mnjuly1970 last updated on 11/Aug/23

{\begin{cases} Ω_{1} = \int_{0}^{\frac{π}{2}} \frac{x^{2}}{{s i n}^{2} (x)} d x \\ \Rightarrow \frac{Ω_{1}}{Ω_{2}} = ? \\ Ω_{2} = \int_{0}^{\frac{π}{2}} \frac{x}{t a n (x)} d x \end{cases}

Answered by sniper237 last updated on 11/Aug/23

b y p a r t s i n t e g r a t i o n Ω_{2} = \frac{1}{2} Ω_{1}