find-the-minimum-value-of-f-x-f-x-x-2-2x-5-4x-2-4x-10-

Question Number 196343 by universe last updated on 23/Aug/23

find the minimum value of f (x)

f (x) = \sqrt{x^{2} - 2 x + 5} + \sqrt{{4 x}^{2} - 4 x + 10}

Answered by MM42 last updated on 23/Aug/23

\sqrt{{(x - 1)}^{2} + 4} + \sqrt{{(2 x - 1)}^{2} + 9}

\Rightarrow m i n \sim 5

Answered by Frix last updated on 23/Aug/23

f (x) = \sqrt{x^{2} - 2 x + 5} + 2 \sqrt{x^{2} - x + \frac{5}{2}}

Solving f^{'} (x) = 0 leads to :

x \approx . 635144580

f (x) \approx 5.04515892

[No useful exact solution possible]

Maybe check the question \dots

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