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xp-x-x-3-2x-2-x-a-p-1-




Question Number 196364 by mathlove last updated on 23/Aug/23
xp(x)=x^3 −2x^2 +x−a  p(−1)=?
$${xp}\left({x}\right)={x}^{\mathrm{3}} −\mathrm{2}{x}^{\mathrm{2}} +{x}−{a} \\ $$$${p}\left(−\mathrm{1}\right)=? \\ $$
Answered by MM42 last updated on 23/Aug/23
x=0⇒a=0  x=−1⇒p(−1)=4
$${x}=\mathrm{0}\Rightarrow{a}=\mathrm{0} \\ $$$${x}=−\mathrm{1}\Rightarrow{p}\left(−\mathrm{1}\right)=\mathrm{4} \\ $$

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