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Question-196498




Question Number 196498 by Pedro2002 last updated on 26/Aug/23
Answered by Frix last updated on 26/Aug/23
∫e^(−x^2 ) dx=((√π)/2)∫(2/( (√π)))e^(−x^2 ) dx=((√π)/2)erf x +C
$$\int\mathrm{e}^{−{x}^{\mathrm{2}} } {dx}=\frac{\sqrt{\pi}}{\mathrm{2}}\int\frac{\mathrm{2}}{\:\sqrt{\pi}}\mathrm{e}^{−{x}^{\mathrm{2}} } {dx}=\frac{\sqrt{\pi}}{\mathrm{2}}\mathrm{erf}\:{x}\:+{C} \\ $$

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