Menu Close

solve-3x-3-2-4x-1-2-1-0-

Tinku Tara 0 Comments
Pin




Question Number 196652 by SANOGO last updated on 28/Aug/23
solve 3x^(3/2) −4x^(1/2) +1=0
solve3x32−4x12+1=0
Answered by BaliramKumar last updated on 28/Aug/23
3((√x))^3 − 3(√x) −(√x) +1 = 0 3(√x)[((√x))^2 −1] −( (√x) −1)= 0 3(√x)[((√x)−1)((√x) +1)] −( (√x) −1)= 0 ((√x)−1)[3((√x))^2 +3(√x) − 1]= 0 (√x) − 1 = 0 or 3((√x))^2 + 3(√x) − 1 =0 (√x) = 1 (√x) = ((−3 ± (√(21)))/6) x = 1 (√x) = ((−3 +(√(21)))/6) or (√x) = ((−3 − (√(21)))/6) (√x) = (√(((−3 + (√(21)))^2 )/(36))) invalid (√x) = (√(((30 − 6(√(21))))/(36))) (√x) = (√((5 − (√(21)))/6)) x = ((5 − (√(21)))/6)
3(x)3−3x−x+1=03x[(x)2−1]−(x−1)=03x[(x−1)(x+1)]−(x−1)=0(x−1)[3(x)2+3x−1]=0x−1=0or3(x)2+3x−1=0x=1x=−3±216x=1x=−3+216orx=−3−216x=(−3+21)236invalidx=(30−621)36x=5−216x=5−216
Answered by Frix last updated on 28/Aug/23
3x^(3/2) −4x^(1/2) +1=0 x≥0 Obviously x=1 ★ ⇒ ((√x)−1)(x−(√x)−(1/3))=0 (√x)=(1/2)+((√(21))/6) ★
3x32−4x12+1=0x⩾0Obviouslyx=1★⇒(x−1)(x−x−13)=0x=12+216★

Pin

Leave a Reply

Your email address will not be published. Required fields are marked *