Question Number 196880 by subheenoy last updated on 02/Sep/23
$$\mathrm{1}.\:{A}\:{container}\:{of}\:{milk}\:{is}\:\frac{\mathrm{4}}{\mathrm{5}}\:{full}.\:{When}\:\mathrm{10}{L}\:{of}\:{milk}\:{is}\:{poured}\:{into}\:{it}\:{the}\:{container}\:{becomes}\:\:\frac{\mathrm{9}}{\mathrm{10}}\:{full}.\:{What}\:{is}\:{the}\:{capacity}\:{of}\:{the}\:{container}? \\ $$
Answered by Frix last updated on 02/Sep/23
$$\frac{\mathrm{4}}{\mathrm{5}}{x}+\mathrm{10}=\frac{\mathrm{9}}{\mathrm{10}}{x} \\ $$$$\mathrm{10}=\left(\frac{\mathrm{9}}{\mathrm{10}}−\frac{\mathrm{4}}{\mathrm{5}}\right){x}=\left(\frac{\mathrm{9}−\mathrm{8}}{\mathrm{10}}\right){x}=\frac{\mathrm{1}}{\mathrm{10}}{x} \\ $$$${x}=\mathrm{100} \\ $$