Question Number 196957 by otchereabdullai@gmail.com last updated on 04/Sep/23
Answered by dimentri last updated on 05/Sep/23
$$\:\:\:\:\frac{\mathrm{9}!}{{x}!\:\left(\mathrm{9}−{x}\right)!}\:=\:\mathrm{4}\left(\frac{\mathrm{7}!}{\left({x}−\mathrm{1}\right)!\left(\mathrm{8}−{x}\right)!}\right) \\ $$$$\:\:\:\:\frac{\mathrm{72}}{{x}\left(\mathrm{9}−{x}\right)}\:=\:\mathrm{4} \\ $$$$\:\:\:\:\mathrm{18}=\:\mathrm{9}{x}−{x}^{\mathrm{2}} \\ $$$$\:\:\:\:\:{x}^{\mathrm{2}} −\mathrm{9}{x}+\mathrm{18}=\mathrm{0} \\ $$$$\:\:\:\:\left({x}−\mathrm{6}\right)\left({x}−\mathrm{3}\right)=\mathrm{0} \\ $$$$\:\:\:\:\:{x}=\mathrm{6}\:{or}\:{x}=\mathrm{3} \\ $$
Commented by otchereabdullai@gmail.com last updated on 05/Sep/23
$${please}\:{can}\:{you}\:{add}\:{the}\:{steps}\:{in}\: \\ $$$${gettimg}\:{the}\:\frac{\mathrm{72}}{{x}\left(\mathrm{9}−{x}\right)}=\mathrm{4} \\ $$