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Question-197018




Question Number 197018 by sonukgindia last updated on 06/Sep/23
Answered by universe last updated on 07/Sep/23
1/3
$$\mathrm{1}/\mathrm{3}\: \\ $$
Commented by MathematicalUser2357 last updated on 10/Sep/23
0.333333
$$\mathrm{0}.\mathrm{333333} \\ $$
Answered by MM42 last updated on 10/Sep/23
((om)/(sin45))=((oh)/(sinm1))   &  ((om)/(sin45))=((oc)/(sinm2))  ⇒((oh)/(oc))=((sinm1)/(sinm2))=(1/2)   ⇒s_(omh) =(1/3)s_(mch) =(1/6)a^2    &  s_(cog) =(2/3)s_(chg) =(1/6)a^2   ⇒s_(blue) =(4/3)a^2  ⇒ (s_(blue) /s_(abcd) )= (1/3)  ✓
$$\frac{{om}}{{sin}\mathrm{45}}=\frac{{oh}}{{sinm}\mathrm{1}}\:\:\:\&\:\:\frac{{om}}{{sin}\mathrm{45}}=\frac{{oc}}{{sinm}\mathrm{2}} \\ $$$$\Rightarrow\frac{{oh}}{{oc}}=\frac{{sinm}\mathrm{1}}{{sinm}\mathrm{2}}=\frac{\mathrm{1}}{\mathrm{2}}\: \\ $$$$\Rightarrow{s}_{{omh}} =\frac{\mathrm{1}}{\mathrm{3}}{s}_{{mch}} =\frac{\mathrm{1}}{\mathrm{6}}{a}^{\mathrm{2}} \:\:\:\&\:\:{s}_{{cog}} =\frac{\mathrm{2}}{\mathrm{3}}{s}_{{chg}} =\frac{\mathrm{1}}{\mathrm{6}}{a}^{\mathrm{2}} \\ $$$$\Rightarrow{s}_{{blue}} =\frac{\mathrm{4}}{\mathrm{3}}{a}^{\mathrm{2}} \:\Rightarrow\:\frac{{s}_{{blue}} }{{s}_{{abcd}} }=\:\frac{\mathrm{1}}{\mathrm{3}}\:\:\checkmark \\ $$$$ \\ $$
Commented by MM42 last updated on 10/Sep/23

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