Question-197027

Question Number 197027 by sonukgindia last updated on 06/Sep/23

Answered by MM42 last updated on 06/Sep/23

c_{1} : x^{2} + y^{2} = 36 & c_{2} : {(x - 10)}^{2} + y^{2} = 36

c_{1}, c_{2} \Rightarrow A = 5, B = 6

v_{1} = \frac{1}{2} \times \frac{4}{3} π \times 6^{3} = 144 π

v_{2} = π \int_{0}^{5} (36 - x^{2}) d x = π (36 x - \frac{x^{3}}{3}) ∣_{0}^{5} = \frac{415 π}{3}

v_{3} = π \int_{5}^{6} (36 - {(x^{2} - 10)}^{2}) d x = π (36 x - \frac{{(x - 10)}^{3}}{3}) ∣_{5}^{6} = \frac{47 π}{3}

v = 307 π ✓

Answered by MM42 last updated on 06/Sep/23

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