Find-all-the-values-of-sin-1-2-

Question Number 197052 by pete last updated on 07/Sep/23

Find all the values of \sin^{- 1} \sqrt{2}

Answered by Frix last updated on 07/Sep/23

\sin x = \sqrt{2}

x = (2 n - \frac{1}{2}) π \pm i \ln (1 + \sqrt{2})

You get this using

\sin x = \frac{e^{i x} - e^{- i x}}{2 i}

Commented by pete last updated on 07/Sep/23

thank you sir

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