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Question-197147




Question Number 197147 by sonukgindia last updated on 08/Sep/23
Answered by Frix last updated on 10/Sep/23
Obviously x=1∨x=(π/2)∨x=((5π)/2) because  ln 1 =0 and sin (π/2) =1
Obviouslyx=1x=π2x=5π2becauseln1=0andsinπ2=1
Commented by sonukgindia last updated on 09/Sep/23
o  think all possibilities
othinkallpossibilities
Answered by MM42 last updated on 09/Sep/23
a=x^(ln(sinx)) ⇒lna=lnx×lnsinx  (i)  b=(sinx)^(lnx) ⇒lnb=lnx×lnsinx   (ii)  (i)=(ii)⇒a=b⇒4a=4⇒a=1  ⇒lnx×lnsinx=0  ⇒lnx=0⇒ determinant (((x=1))) ✓  or  lnsinx=0  ⇒sinx=1⇒ determinant (((x=2kπ+(π/2)))) ✓
a=xln(sinx)lna=lnx×lnsinx(i)b=(sinx)lnxlnb=lnx×lnsinx(ii)(i)=(ii)a=b4a=4a=1lnx×lnsinx=0lnx=0x=1orlnsinx=0sinx=1x=2kπ+π2
Commented by MM42 last updated on 09/Sep/23
Commented by MathematicalUser2357 last updated on 10/Sep/23
That′s Desmos
ThatsDesmos

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