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log-2-0-30103-log-125-

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Question Number 197251 by sciencestudentW last updated on 11/Sep/23
log 2=0.30103 log 125=?
log2=0.30103log125=?
Answered by mr W last updated on 26/Sep/23
log 2=a log 125=log 5^3 =3 log 5=3( log 10−log 2) =3(1−a)=3(1−0.30103)=2.09691
log2=alog125=log53=3log5=3(log10−log2)=3(1−a)=3(1−0.30103)=2.09691

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