log-3-12-a-log-3-18-

Question Number 197253 by sciencestudentW last updated on 11/Sep/23

lo \underset{3}{g 12} = a

\log \underset{3}{} 18 = ?

Answered by AST last updated on 11/Sep/23

\frac{l o g 3 + 2 l o g 2}{l o g 3} = a \Rightarrow 2 l o g 2 = (a - 1) l o g 3

\frac{l o g 2 + 2 l o g 3}{l o g 3} = \frac{l o g 2}{l o g 3} + 2 = \frac{a - 1}{2} + 2 = \frac{a + 3}{2}

Facebook Tweet Pin