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log-a-x-30-log-b-x-70-log-ab-x-




Question Number 197252 by sciencestudentW last updated on 11/Sep/23
log_a x=30  log_b x=70  log_(ab) x=?
logax=30logbx=70logabx=?
Answered by AST last updated on 11/Sep/23
((logx)/(loga))=30;((logx)/(logb))=70⇒((logb+loga)/(logx))=(1/(21))  ⇒log_(ab) x=((logx)/(loga+logb))=21
logxloga=30;logxlogb=70logb+logalogx=121logabx=logxloga+logb=21

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