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lim-x-0-sin-2-x-sin-x-2-x-2-cos-2-x-cos-x-2-




Question Number 197282 by cortano12 last updated on 12/Sep/23
      lim_(x→0)  ((sin^2 x−sin x^2 )/(x^2  (cos^2 x−cos x^2  ))) =?
limx0sin2xsinx2x2(cos2xcosx2)=?
Answered by MM42 last updated on 12/Sep/23
lim_(x→0)  ((sin^2 x−x^2 +x^2 −sinx^2 )/(x^2 (cos^2 x−1+1−cosx^2 )))  =lim_(x→0)  (((sinx+x)(sinx−x)+(1/6)x^6 )/(x^2 ((cosx−1)(cosx+1)+(1/2)x^4 )))  =lim_(x→0)  (((2x)(−(1/6)x^3 )+(1/6)x^6 )/(x^2 ((−(1/2)x^2 )(cosx+1)+(1/2)x^4 )))  =lim_(x→0)  ((−(1/3)x^4 +(1/6)x^6 )/(−x^4 +(1/2)x^6 ))=(1/3) ✓
limx0sin2xx2+x2sinx2x2(cos2x1+1cosx2)=limx0(sinx+x)(sinxx)+16x6x2((cosx1)(cosx+1)+12x4)=limx0(2x)(16x3)+16x6x2((12x2)(cosx+1)+12x4)=limx013x4+16x6x4+12x6=13

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