lim-x-4x-4x-2-5-2x-1-bx-

Question Number 197548 by cortano12 last updated on 21/Sep/23

\lim_{x \to - \infty} {(\frac{4 x - \sqrt{{4 x}^{2} + 5}}{2 x - 1})}^{bx} = ?

Answered by MM42 last updated on 21/Sep/23

{l i m}_{x \to - \infty} {(\frac{4 x - ∣ 2 x ∣}{2 x - 1})}^{b x} = {l i m}_{x \to - \infty} {(3)}^{b x} = {\begin{cases} 0; b > 0 \\ + \infty; b < 0 \end{cases}

Commented by cortano12 last updated on 21/Sep/23

wrong