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lim-x-4x-4x-2-5-2x-1-bx-




Question Number 197548 by cortano12 last updated on 21/Sep/23
    lim_(x→−∞)  (((4x−(√(4x^2 +5)))/(2x−1)))^(bx) =?
$$\:\:\:\:\underset{{x}\rightarrow−\infty} {\mathrm{lim}}\:\left(\frac{\mathrm{4x}−\sqrt{\mathrm{4x}^{\mathrm{2}} +\mathrm{5}}}{\mathrm{2x}−\mathrm{1}}\right)^{\mathrm{bx}} =?\: \\ $$
Answered by MM42 last updated on 21/Sep/23
lim_(x→−∞)  (((4x−∣2x∣)/(2x−1)))^(bx) =lim_(x→−∞)  (3)^(bx)  = { (( 0       ;  b>0)),((+∞   ;  b<0)) :}
$${lim}_{{x}\rightarrow−\infty} \:\left(\frac{\mathrm{4}{x}−\mid\mathrm{2}{x}\mid}{\mathrm{2}{x}−\mathrm{1}}\right)^{{bx}} ={lim}_{{x}\rightarrow−\infty} \:\left(\mathrm{3}\right)^{{bx}} \:=\begin{cases}{\:\mathrm{0}\:\:\:\:\:\:\:;\:\:{b}>\mathrm{0}}\\{+\infty\:\:\:;\:\:{b}<\mathrm{0}}\end{cases} \\ $$
Commented by cortano12 last updated on 21/Sep/23
wrong
$$\mathrm{wrong} \\ $$

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