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x-a-x-a-4-where-a-Z-solve-for-x-by-showing-steps-




Question Number 197708 by karowan last updated on 26/Sep/23
  x^a =x^(a+4)   where a∈Z  solve for x by showing steps
xa=xa+4whereaZsolveforxbyshowingsteps
Answered by Frix last updated on 26/Sep/23
x^(a+4) −x^a =0  x^a (x−1)(x+1)(x^2 +1)=0  a>0∧x=0  x=±1  x=±i
xa+4xa=0xa(x1)(x+1)(x2+1)=0a>0x=0x=±1x=±i
Commented by karowan last updated on 26/Sep/23
correct

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