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I-2-6-x-1-x-1-dx-




Question Number 197802 by cortano12 last updated on 29/Sep/23
   I=∫_(−2) ^6  ((∣x−1∣)/(x−1)) dx =?
$$\:\:\:\mathrm{I}=\underset{−\mathrm{2}} {\overset{\mathrm{6}} {\int}}\:\frac{\mid\mathrm{x}−\mathrm{1}\mid}{\mathrm{x}−\mathrm{1}}\:\mathrm{dx}\:=? \\ $$
Answered by MM42 last updated on 29/Sep/23
I=∫_(−2) ^1 −dx+∫_1 ^6 dx=−3+5=2✓
$${I}=\int_{−\mathrm{2}} ^{\mathrm{1}} −{dx}+\int_{\mathrm{1}} ^{\mathrm{6}} {dx}=−\mathrm{3}+\mathrm{5}=\mathrm{2}\checkmark \\ $$

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