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Question-198062




Question Number 198062 by NANIGOPAL last updated on 09/Oct/23
Commented by mr W last updated on 10/Oct/23
equality −2 can not hold!  equality ((3(√3))/2) holds at A=B=20°, C=140°.  −2<sin 3A+sin 3B+sin 3C≤((3(√3))/2)
$${equality}\:−\mathrm{2}\:{can}\:{not}\:{hold}! \\ $$$${equality}\:\frac{\mathrm{3}\sqrt{\mathrm{3}}}{\mathrm{2}}\:{holds}\:{at}\:{A}={B}=\mathrm{20}°,\:{C}=\mathrm{140}°. \\ $$$$−\mathrm{2}<\mathrm{sin}\:\mathrm{3}{A}+\mathrm{sin}\:\mathrm{3}{B}+\mathrm{sin}\:\mathrm{3}{C}\leqslant\frac{\mathrm{3}\sqrt{\mathrm{3}}}{\mathrm{2}} \\ $$

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