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if-a-x-y-b-is-an-AP-and-a-p-q-b-is-a-GP-prove-that-xy-pq-with-a-b-gt-0-




Question Number 198147 by mr W last updated on 11/Oct/23
if a,x,y,b is an AP and a,p,q,b is a GP.  prove that xy≥pq.  (with a, b >0)
ifa,x,y,bisanAPanda,p,q,bisaGP.provethatxypq.(witha,b>0)
Answered by AST last updated on 11/Oct/23
p^2 =aq;q^2 =pb⇒p^2 q^2 =abpq⇒pq=ab  2x=a+y;2y=x+b⇒4xy=(a+y)(x+b)  3xy=ax+ab+yb≥^? 3pq=3ab  ⇔ax+yb≥2ab  ⇔a(a+d)+(a+2d)(a+3d)≥2(a)(a+3d)  a^2 +ad+a^2 +3ad+2ad+6d^2 ≥2a^2 +6ad  ⇔d^2 ≥0(true).. Hence 3xy≥3ab⇒xy≥ab=pq  Equality holds when d=0 ⇒ a=b=x=y=p=q
p2=aq;q2=pbp2q2=abpqpq=ab2x=a+y;2y=x+b4xy=(a+y)(x+b)3xy=ax+ab+yb?3pq=3abax+yb2aba(a+d)+(a+2d)(a+3d)2(a)(a+3d)a2+ad+a2+3ad+2ad+6d22a2+6add20(true)..Hence3xy3abxyab=pqEqualityholdswhend=0a=b=x=y=p=q
Commented by mr W last updated on 11/Oct/23
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