Question Number 198187 by Tawa11 last updated on 13/Oct/23
Commented by Blackpanther last updated on 13/Oct/23
$$\mathrm{0}.\mathrm{1} \\ $$
Answered by mr W last updated on 13/Oct/23
Commented by mr W last updated on 13/Oct/23
$$\mathrm{2}×\mathrm{0}.\mathrm{5}=\mathrm{10}×\left(\mathrm{0}.\mathrm{5}−{x}\right) \\ $$$$\Rightarrow{x}=\mathrm{0}.\mathrm{4} \\ $$$$\Rightarrow{gravity}\:{center}\:{is}\:\mathrm{0}.\mathrm{4}\:{m}\:{apart}\:{from} \\ $$$${the}\:{other}\:{end}\:{of}\:{the}\:{rod}. \\ $$
Commented by Tawa11 last updated on 13/Oct/23
$$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir}. \\ $$$$\mathrm{I}\:\mathrm{appreciate}\:\mathrm{your}\:\mathrm{time}. \\ $$