let-a-R-z-C-resolve-z-1-n-e-ipina-deduce-that-P-n-k-0-n-1-sin-a-kpi-n-

Question Number 198357 by pticantor last updated on 18/Oct/23

l e t a \in R, z \in C

r e s o l v e

{(z + 1)}^{n} = e^{i π n a}

d e d u c e t h a t P_{n} = \underset{k = 0}{\prod^{n - 1}} s i n (a + \frac{k π}{n})