Question Number 198477 by a.lgnaoui last updated on 20/Oct/23

Commented by a.lgnaoui last updated on 20/Oct/23

Commented by mr W last updated on 21/Oct/23

Answered by mr W last updated on 21/Oct/23

Commented by mr W last updated on 21/Oct/23
![b^2 =d^2 +f^2 ...(i) a^2 =c^2 +(f+c+d)^2 =c^2 +f^2 +c^2 +d^2 +2fc+2fd+2cd ...(ii) (ii)−(i): a^2 −b^2 =2c^2 +2fc+2fd+2cd ⇒c^2 +fc+fd+cd=((a^2 −b^2 )/2) [ABCD]=(df/2)+((c(f+c+d))/2) =((c^2 +df+cf+cd)/2)=((a^2 −b^2 )/4) ✓](https://www.tinkutara.com/question/Q198520.png)
Commented by a.lgnaoui last updated on 21/Oct/23
