Question Number 198517 by hardmath last updated on 21/Oct/23
Commented by Hridiana last updated on 21/Oct/23
$${a}×\mathrm{4}+\frac{{a}}{\mathrm{2}}\:{going}\:{to}\:{a}_{\mathrm{1}} \\ $$
Commented by Hridiana last updated on 21/Oct/23
$${okay}.\:\mathrm{4}+{a}+\left(\mathrm{3}+\mathrm{1}/{a}\right) \\ $$$$\mathrm{6}{b}\sqrt{{ab}−{c}}+\mathrm{3} \\ $$$$\sqrt{{a}}\sqrt{{bc}}\:{is}\:{in}\:\left\{{a}>\mathrm{0}\right\} \\ $$
Answered by Hridiana last updated on 21/Oct/23
$${a}\sqrt{{z}} \\ $$