Question Number 198749 by ajfour last updated on 23/Oct/23
![Find area bounded by curve below cx^3 +c^2 +y(y+1)^2 =x^2 y+cx(3y+1)](https://www.tinkutara.com/question/Q198749.png)
$${Find}\:{area}\:{bounded}\:{by}\:{curve}\:{below} \\ $$$${cx}^{\mathrm{3}} +{c}^{\mathrm{2}} +{y}\left({y}+\mathrm{1}\right)^{\mathrm{2}} ={x}^{\mathrm{2}} {y}+{cx}\left(\mathrm{3}{y}+\mathrm{1}\right) \\ $$