Question Number 199023 by mr W last updated on 26/Oct/23
Commented by mr W last updated on 26/Oct/23
$${if}\:{AX}={YB},\:{prove}\:\angle{ADX}=\angle{YDC}. \\ $$
Answered by mr W last updated on 27/Oct/23
Commented by mr W last updated on 27/Oct/23
$${AD}={YO}={radius} \\ $$$$\Delta{ADX}\equiv\Delta{YOB} \\ $$$$\angle{ADX}=\angle{YOB}=\alpha=\angle{COB} \\ $$$$\angle{YDC}=\beta=\frac{\angle{YOC}}{\mathrm{2}}=\alpha=\angle{YOB}=\angle{ADX} \\ $$$$\Rightarrow{proved} \\ $$