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8-x-1-1-4-x-1-x-1-1-4-5-x-2-1-2-3-1-4-x-




Question Number 199159 by cortano12 last updated on 28/Oct/23
 ((8(x+1)))^(1/4)  +(((x+1)/(x−1)))^(1/4)  =((5(x^2 +1)^2 −3))^(1/4)     x=?
$$\:\sqrt[{\mathrm{4}}]{\mathrm{8}\left(\mathrm{x}+\mathrm{1}\right)}\:+\sqrt[{\mathrm{4}}]{\frac{\mathrm{x}+\mathrm{1}}{\mathrm{x}−\mathrm{1}}}\:=\sqrt[{\mathrm{4}}]{\mathrm{5}\left(\mathrm{x}^{\mathrm{2}} +\mathrm{1}\right)^{\mathrm{2}} −\mathrm{3}}\: \\ $$$$\:\mathrm{x}=? \\ $$
Answered by Frix last updated on 28/Oct/23
You can only approximate  x_1 ≈2.14869836  x_(2, 3) ≈−.757880309±.164353877i  x_(4, 5) ≈−.251846484±2.21603434i
$$\mathrm{You}\:\mathrm{can}\:\mathrm{only}\:\mathrm{approximate} \\ $$$${x}_{\mathrm{1}} \approx\mathrm{2}.\mathrm{14869836} \\ $$$${x}_{\mathrm{2},\:\mathrm{3}} \approx−.\mathrm{757880309}\pm.\mathrm{164353877i} \\ $$$${x}_{\mathrm{4},\:\mathrm{5}} \approx−.\mathrm{251846484}\pm\mathrm{2}.\mathrm{21603434i} \\ $$

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